4x-x^3/x^2-9=4x

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Solution for 4x-x^3/x^2-9=4x equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x-((x^3)/(x^2))-9 = 4*x // - 4*x

4*x-((x^3)/(x^2))-(4*x)-9 = 0

4*x-x-4*x-9 = 0

-x-9 = 0 // + 9

-x = 9 // * -1

x = -9

x = -9

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